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Bonding and Reactivity of a Pair of Neutral and Cationic Heterobimetallic RuZn2 Complexes.


ABSTRACT: A combined experimental and computational study of the structure and reactivity of two [RuZn2Me2] complexes, neutral [Ru(PPh3)(Ph2PC6H4)2(ZnMe)2] (2) and cationic [Ru(PPh3)2(Ph2PC6H4)(ZnMe)2][BArF4] ([BArF4] = [B{3,5-(CF3)2C6H3}4]) (3), is presented. Structural and computational analyses indicate these complexes are best formulated as containing discrete ZnMe ligands in which direct Ru-Zn bonding is complemented by weaker Zn···Zn interactions. The latter are stronger in 2, and both complexes exhibit an additional Zn···Caryl interaction with a cyclometalated phosphine ligand, this being stronger in 3. Both 2 and 3 show diverse reactivity under thermolysis and with Lewis bases (PnBu3, PCy3, and IMes). With 3, all three Lewis bases result in the loss of [ZnMe]+. In contrast, 2 undergoes PPh3 substitution with PnBu3, but with IMes, loss of ZnMe2 occurs to form [Ru(PPh3)(C6H4PPh2)(C6H4PPhC6H4Zn(IMes))H] (7). The reaction of 3 with H2 affords the cationic trihydride complex [Ru(PPh3)2(ZnMe)2(H)3][BArF4] (12). Computational analyses indicate that both 12 and 7 feature bridging hydrides that are biased toward Ru over Zn.

SUBMITTER: Miloserdov FM 

PROVIDER: S-EPMC8730504 | biostudies-literature | 2021 Nov

REPOSITORIES: biostudies-literature

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Bonding and Reactivity of a Pair of Neutral and Cationic Heterobimetallic RuZn<sub>2</sub> Complexes.

Miloserdov Fedor M FM   Pécharman Anne-Frédérique AF   Sotorrios Lia L   Rajabi Nasir A NA   Lowe John P JP   Macgregor Stuart A SA   Mahon Mary F MF   Whittlesey Michael K MK  

Inorganic chemistry 20211018 21


A combined experimental and computational study of the structure and reactivity of two [RuZn<sub>2</sub>Me<sub>2</sub>] complexes, neutral [Ru(PPh<sub>3</sub>)(Ph<sub>2</sub>PC<sub>6</sub>H<sub>4</sub>)<sub>2</sub>(ZnMe)<sub>2</sub>] (<b>2</b>) and cationic [Ru(PPh<sub>3</sub>)<sub>2</sub>(Ph<sub>2</sub>PC<sub>6</sub>H<sub>4</sub>)(ZnMe)<sub>2</sub>][BAr<sup>F</sup><sub>4</sub>] ([BAr<sup>F</sup><sub>4</sub>] = [B{3,5-(CF<sub>3</sub>)<sub>2</sub>C<sub>6</sub>H<sub>3</sub>}<sub>4</sub>]) (<b>3</b  ...[more]

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